Learning Journey

Friday, 9 December 2016

My strategy


STRATEGY STAGE 5  Bailey
Early Additive - Part-Whole

This first section is about addition and subtraction.  I can do this.   I can’t do this yet.




Solve simple problems mentally using basic facts they know:
- Doubles: 8+7 = 8+8-1

8 + 7 =

Solve this problem using the doubles strategy.
6 + 7 =
- Fives:
Example:
8+7= 5+3+5+2
Solve this problem using the fives strategy.
7 + 6 =

- Making Tens:

Example:
8+7=8+2+5
Solve this problem using the Making Tens strategy.
7 + 5 =
Solve 2&3 digit problems by:

-Tidy Numbers:
 

Example:
29+18 as 30+17

Solve this problem using the Tidy Numbers strategy.
37 + 15 =
- Place Value:

Example:
33+16 as 30+10+3+6

Solve this problem using the Place Value strategy
37 + 15 =

-Using rounding and compensating to solve addition problems
Example
I can solve 29  + 29 =
by doing 30 + 30 =60
Then, 60 - 2 = 58
So, 29 + 29 = 58
Solve this addition problem using rounding and compensation.
19 + 19 =
I can use rounding and compensating to solve subtraction problems
Example
I can solve 28 - 9 =
by doing 28 - 10  =18
Then, 18 +1 = 19
So, 28 - 9 = 19
Solve this subtraction problem using rounding and compensation

37 - 9 =
Reflection/Comment: There aren’t any answers on here as you worked these out on paper and this page just shows whether or not you could solve certain kinds of problem. You got 6/7 which is pretty good. You are definitely ready to move up to Stage 6 thinking but you do need to re-do some lessons about rounding and compensation. Mrs B๐Ÿ˜€
I am quite happy with how I did. ๐Ÿ˜•




Strategy Stage 5  Level 2       This is what I can do and  what I can’t do yet.
This next section is about multiplication and division.    Bailey T4 2016
Solve problems by:
- using repeated addition with problems involving 2’s, 3’s, 4’s, 5’s and 10’s at least
Example: 6 x 5 =

5 +5+5+5+5+5 =
Solve this problem by using the Repeated Addition strategy.


6 x 4 =

- or forming the factors when the basic fact is known
Example:

I know that 6 x 5 = 30  so I can solve this missing number problem.

6 x ______ = 30

Solve this missing number problem by using this known fact.
8 x 4 = 32
So


8 x _______ = 32
The next section is about fractions.
- Find a fraction of a number by trial and improvement with addition facts

Example:
⅓ of 12 =
Solve this fraction problem by using addition facts.
What is ¼ of 8?
- Find fractions of shapes and lengths including fractions greater than 1  
Example:
This shape shows ½





These shapes show
1  and a half







Draw a shape to show






Draw shapes to show
¼







1 and a quarter
Reflection/Comment:  There aren’t any answers on here as you worked these out on paper and this page just shows whether or not you could solve certain kinds of problem. You need to go back to Maths Buddy and re-do some exercises about finding fractions of numbers, shapes and lengths, especially fractions which are bigger than 1.
Mrs B๐Ÿ˜€
I’m happy that I did well in multiplication. Fractions are tricky.๐Ÿ˜•



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